Determine the number of mono-chloro products | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reactant is isopropylcyclopentane. To find the number of structural mono-chloro products,we identify all non-equivalent hydrogen atoms in the

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) The reactant is isopropylcyclopentane. To find the number of structural mono-chloro products,we identify all non-equivalent hydrogen atoms in the molecule.$1$. The isopropyl group has a tertiary hydrogen at the junction $(CH)$ and six equivalent primary hydrogens on the two methyl groups $(CH_3)$. This gives $2$ products.$2$. The cyclopentane ring has five carbons. The carbon attached to the isopropyl group is a tertiary carbon $(CH)$. The two adjacent carbons $(CH_2)$ are equivalent,and the two carbons further away $(CH_2)$ are also equivalent.$3$. Thus,the distinct positions for substitution are:- Tertiary $H$ on the isopropyl group ($1$ product).- Primary $H$ on the methyl groups ($1$ product).- Tertiary $H$ on the cyclopentane ring ($1$ product).- Secondary $H$ on the carbons adjacent to the isopropyl group ($1$ product).- Secondary $H$ on the carbons further from the isopropyl group ($1$ product).Total structural isomers = $1 + 1 + 1 + 1 + 1 = 5$.

Determine the number of mono-chloro products (structural isomers only) formed by the reaction of isopropylcyclopentane with $Cl_2/\Delta$.

Similar Questions

Identify the product $Z$ in the following series of reactions: $CH_3CH_2OH$ $\xrightarrow{SOCl_2, \Delta} X$ $\xrightarrow{Mg, \text{Dry ether}} Y$ $\xrightarrow{NH_3} Z + Mg(Cl)(NH_2)$

What is the use of $tetraethyl$ lead $(TEL)$?

Product $(A)$ is

In Wurtz reaction,the reagent used is

$Ph-CH=NO_2H$ $\xrightarrow[{3 \ days}]{{isomerises}}$ $\mathop {(x)}\limits_{(50-50\%)}$,Isomer $(x)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module